原题下载 USACO2016-FEB-G2 答案 (Analysis by Nathan Pinsker) Although kk is rather small, trying all possible positions for the doors is O((nk))O((nk)) and is still way too slow. Sometimes it's help...
原题下载 USACO2016-FEB-G1 答案 (Analysis by Nathan Pinsker) The first solution to this problem that people will likely come up with is something like the following: process each of the cows in some...
原题下载 USACO2016-FEB-S3 答案 (Analysis by Nick Wu) In this problem, we have two buckets and we can either fill them, empty them, or pour one into the other until we fill a bucket or empty one. We...
原题下载 答案 (Analysis by Nick Wu) In the bronze version of this problem, we naively tried all possible pairs of vertical fences and horizontal fences as long as they were next to a cow. Because t...
原题下载 USACO2016-FEB-S1 答案 (Analysis by Nathan Pinsker) The first solution to this problem that people will likely come up with is something like the following: process each of the cows in some...
原题下载 USACO2016-FEB-B3 答案 (Analysis by Nick Wu) There are a lot of possible fence combinations to consider - if we simply consider every possible even x-coordinate and every possible event y-c...
原题下载 USACO2016-FEB-B2 答案 (Analysis by Nick Wu) For this problem, we can try unlocking all possible starting doors and seeing how far each cow travels. One tricky implementation detail here is...
原题下载 USACO2016-FEB-B1 答案 (Analysis by Nick Wu) It isn't immediately clear how to fill the larger bucket using the size X bucket and the size Y bucket. Instead of trying to cleverly figure out...
原题下载 USACO2017-FEB-B2 答案 import java.io.*; import java.util.*; public class circlecross { public static void main(String[] args) throws IOException { BufferedReader br = new BufferedReader(ne...
